1 point Find the value of the standard normal random variabl
Solution
A)
We get the z score from the given left tailed area. As      
       
 Left tailed area =    0.8418  
       
 Then, using table or technology,      
       
 z =    1.001883215   [ANSWER]
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b)
Here, the left tailed area of -zo is (1-0.3766)/2 = 0.3117.
We get the z score from the given left tailed area. As      
       
 Left tailed area =    0.3117  
       
 Then, using table or technology,      
       
 -z =    -0.491037394  
Thus,
z = 0.491037394 [ANSWER]
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c)
Here, the left tailed area of -zo is (1-0.2024)/2 = 0.3988.
We get the z score from the given left tailed area. As      
       
 Left tailed area =    0.3988  
       
 Then, using table or technology,      
       
 -z =    -0.256454383  
Thus,
z = 0.256454383 [ANSWER]
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d)
We get the z score from the given left tailed area. As      
       
 Left tailed area = 1 - 0.3824 =   0.6176  
       
 Then, using table or technology,      
       
 z =    0.29918355   [ANSWER]
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