1 point Find the value of the standard normal random variabl
Solution
A)
We get the z score from the given left tailed area. As
Left tailed area = 0.8418
Then, using table or technology,
z = 1.001883215 [ANSWER]
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b)
Here, the left tailed area of -zo is (1-0.3766)/2 = 0.3117.
We get the z score from the given left tailed area. As
Left tailed area = 0.3117
Then, using table or technology,
-z = -0.491037394
Thus,
z = 0.491037394 [ANSWER]
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c)
Here, the left tailed area of -zo is (1-0.2024)/2 = 0.3988.
We get the z score from the given left tailed area. As
Left tailed area = 0.3988
Then, using table or technology,
-z = -0.256454383
Thus,
z = 0.256454383 [ANSWER]
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d)
We get the z score from the given left tailed area. As
Left tailed area = 1 - 0.3824 = 0.6176
Then, using table or technology,
z = 0.29918355 [ANSWER]
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