Find a basis of the column space of the matrix A 2 4 2 0 2
Find a basis of the column space of the matrix A = [2 -4 -2 0 2 -4 0 2 8 -16 -4 4].
Solution
1. Add (-1 * row_1) to row_2:
2. Add (-4 * row_1) to row_3:
3. Add (-2 * row_ 2) to row_3:
The matrix has 2 pivots
(2)
Because we have found pivots in columns 0 and 2. We know that these columns in the original matrix define the Column Space of the matrix.
Therefore, the Column Space is given by the following equation:
| 2 | -4 | -2 | 0 |
| 0 | 0 | 2 | 2 |
| 8 | -16 | -4 | 4 |
![Find a basis of the column space of the matrix A = [2 -4 -2 0 2 -4 0 2 8 -16 -4 4]. Solution1. Add (-1 * row_1) to row_2: 2. Add (-4 * row_1) to row_3: 3. Add Find a basis of the column space of the matrix A = [2 -4 -2 0 2 -4 0 2 8 -16 -4 4]. Solution1. Add (-1 * row_1) to row_2: 2. Add (-4 * row_1) to row_3: 3. Add](/WebImages/29/find-a-basis-of-the-column-space-of-the-matrix-a-2-4-2-0-2-1078903-1761566278-0.webp)