An object is placed 145 cm in fromt of a convex mirror that

An object is placed 14.5 cm in fromt of a convex mirror that has a focal of -22.5 cm determine the locat In the above figures f located at the focal pout of the lens For each enter T or F. An object placed to the left of and the lens in Fig b produces a virtual image An object placed to the left of f m Fig b remit in an image on the right side of the lent An object placed between f and the lens m Fig a results ui an image on the right tide of the lens An object placed between f and the lens in Fig. a produces a real image The lens in Fig b is converging lens An object placed to the left of f in Fig a an image on the right side of the lens An object placed to the left of f and the leas m Fig a produces a virtual imager A 0.54 cm high object is placed 8 4 cm in from of a lens whose focal length is -7.5 cm What.. the height

Solution

3. f =-22.5cm
do =14.5 cm (distance of object)
di = ? (distance of image)

Acc to mirror equation

1/f = 1/do + 1/di
Solving for 1/di = 1/f - 1/do
di = (1/-22.5 - 1/14.5)^-1 = -8.82 cm.

The image is located behind the mirror (negative sign).

4. a) size of the image for convex mirror, M = -di/do = 8.82/14.5 = 0.61

For concave mirror, f= 22.5 cm

di = (1/22.5-1/14.5)^-1 = -40.78 cm

size of the image for concave mirror, M = 40.78/14.5 = 2.81

5.(A) T (B) F (C) T (D) F (E) F (F) T (G) F

6. Distance of the image, di = (1/-7.5-1/8.4)^-1 = -3.96 cm

hi/ho =di/do

Height of the image, hi = -(3.96/8.4)*0.54 = -0.25 cm

7.  The object is located in front of F that is distance of object is < f(16.5 cm) of lens.

8. The image is located behind F that is distance of image is > f(16.5 cm) of lens.