Two point charges of magnitude 30 x 109 C and 60 x 109 C arc
Two point charges of magnitude 3.0 x 10^-9 C and 6.0 x 10^-9 C arc separated by a distance of 0.30 m. Find the electric force of repulsion between them.
Solution
Force of repulsion = KQ1Q2/(distance)2
K=9x109 Nm2/C2, Q1=3.0x10-9 C, Q2=6.0x10-9 C, distance=0.30m
Force of repulsion = 9x109 x 3.0x10-9 x 6.0x10-9 / (0.30)2 =18 x 10-7 N
