1 If sintheta 713 and theta is in quadrant 2 find costheta 2

1. If sin(theta)= 7/13 and theta is in quadrant 2, find cos(theta).

2. Suppose that tan(t)= -11/4 and that t is in quadrant 1. Find the exact value of sec(t).

Solution

1. If sin(theta)= 7/13 and theta is in quadrant 2, find cos(theta).

cos(theta) = - sqrt( 1- sin^2(theta)    [ cos(theta) is +ve in QII]

= -sqrt( 1- (7/13)^2 0

= - sqrt(120/169) = -2sqrt(30)/13

2. Suppose that tan(t)= 11/4 and that t is in quadrant 1. Find the exact value of sec(t).

If t is quadrant 1 then all trig functions tant , cost ,sint would be +ve

hypotenuse of right angled triangle = sqrt(11^2 +4^2)

= sqrt(137)

sect = 1/cost = sqrt(137)/4       

1. If sin(theta)= 7/13 and theta is in quadrant 2, find cos(theta). 2. Suppose that tan(t)= -11/4 and that t is in quadrant 1. Find the exact value of sec(t).So

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