3 If you add 04mL of an ACh stock solution to 20 mL of Tyrod

3. If you add 0.4mL of an ACh stock solution to 20 mL of Tyrode’s and found that you now have a final [ACh] of 2 x 10­6M in Tyrode’s, what was the [ACh] in the original stock solution?

Solution

Answer:

0.4mL + 20 mL diluent= 20/0.2 = 50 fold dilution

Concentration of ACh = 2x 10^-6 M

Original stock = Diluted stock x Fold dilution

Original stock= 2 x 10­^6M x 50

Original stock= 100 x 10­^6M

3. If you add 0.4mL of an ACh stock solution to 20 mL of Tyrode’s and found that you now have a final [ACh] of 2 x 10­6M in Tyrode’s, what was the [ACh] in the

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