If sigma a n converges and b n converges then sigma a n b n

If sigma a_ n converges and (b_ n) converges, then sigma a_ n b_ n converges.

Solution

Answer :

Let ( bn ) converges then ( bn ) is monotonic and bounded.

Suppose bn b R . Since ( bn ) is monotonic . we either bn+1 bn for all n ( non - decreasing ) or bn+1 bn for all n ( non - increasing ) .

Assume, without loss of generality, that ( bn ) is monotonic non- decreasing, otherwise consider - bn

if ( bn ) is non - decreasing then bn b for all n.

Consider cn = b - bn we have that an converges, the partial sum An of an form a bounded sequence;

C0 C1 C2 C3 . . . Cn 0

Thus by known fact , that anbn converges.

 If sigma a_ n converges and (b_ n) converges, then sigma a_ n b_ n converges.SolutionAnswer : Let ( bn ) converges then ( bn ) is monotonic and bounded. Suppos

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