Find the absolute maximum value and the absolute minimum val

Find the absolute maximum value and the absolute minimum value of the function, if they exist
f(x)=x-ln(x) on (1/2,8)

I would really appreciate it if you could show all the steps. than you

f(x)=x-ln(x) f\'(x) = 1 - 1/x Therefore in the interval (1/2 , 1) f\'(x) = +ve So it first decreases then increases Therefore Absolute max = f(8) = 8 - ln(8) = 5.92 Absolute min = f(1) = 1 - ln(1) = 1