Homework SourseIn a large jobtraining program 60 of the participants are me
In a large job-training program, 60% of the participants are men and 40% are women. An evaluator randomly identified a sample of 5 participants to estimate participate satisfaction with the program.
1. What is the probability the sample of 5 participants will not include any men?
2. What is the probability the sample of 5 participants will not include exactly 2 women?
In a large job-training program, 60% of the participants are men and 40% are women. An evaluator randomly identified a sample of 5 participants to estimate participate satisfaction with the program.
1. What is the probability the sample of 5 participants will not include any men?
2. What is the probability the sample of 5 participants will not include exactly 2 women?
In a large job-training program, 60% of the participants are men and 40% are women. An evaluator randomly identified a sample of 5 participants to estimate participate satisfaction with the program.
1. What is the probability the sample of 5 participants will not include any men?
2. What is the probability the sample of 5 participants will not include exactly 2 women?
Solution
We have Pmen = 0.60 , Pwomen = 0.40, n= 5
1. Not include any men means all 5 members will women
p ( will not include any men ) = 0.45 = 0.01
2. The event Not include exactly 2 women is compliment of include exactly 2 women.
Out of 5, 2 will be women hence remaining three will be men.
p ( include exactly 2 women ) = 0.42 * 0.63 = 0.0346
p ( not include exactly 2 women ) = 1 - p ( include exactly 2 women ) = 1 - 0.0346 = 0.9654
