Convert the following C program to MIPS assembly code a00 i1

Convert the following C program to MIPS assembly code

a=0.0;

i=10;

while (i>0)

{

i=i-1;

a=a*B[i];

}

where a is a single-precision floating-point number stored in register $f0, i is an integer stored in register $s0, and B is a single-precision floating-point array with starting address stored in register $s1.

Solution

Answer:

MIPS Assembly Language Code:

main:
push rbp
mov rbp, rsp
mov DWORD PTR [rbp-4], 0
mov DWORD PTR [rbp-8], 10
.L3:
cmp DWORD PTR [rbp-8], 0
jle .L2
sub DWORD PTR [rbp-8], 1
mov eax, DWORD PTR [rbp-8]
cdqe
mov eax, DWORD PTR [rbp-48+rax*4]
mov edx, DWORD PTR [rbp-4]
imul eax, edx
mov DWORD PTR [rbp-4], eax
jmp .L3
.L2:
mov eax, 0
pop rbp
ret