1 The initial clinical trials of the drug EXTREMESolution1 g

1.) The initial clinical trials of the drug EXTREME

Solution

1)

given

p = 2.2% = 0.022

n = size of sample = 450

mean = np = 450 * 0.022 = 9.9

standard deviation = sqrt(n*p*(1-p)) = sqrt(450 * 0.022 * 0.978) = 3.11

2)

n = 8

p =0.9

q= 1-p = 0.1

for binomial distribuiton

P(X=x) = ncx p^x * q^(1-x)

P(X>=6) = P(x=6) + P(x=7) + P(x=8)

= 8C6 * 0.9^6 * 0.1^2 + 8C7 * 0.9^7 * 0.1 + 8C8 * 0.9^8

= 0.962

hence correct choice is A

1.) The initial clinical trials of the drug EXTREMESolution1) given p = 2.2% = 0.022 n = size of sample = 450 mean = np = 450 * 0.022 = 9.9 standard deviation =

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site