suppose it iss known that 40 of radio listeneres at a partic
suppose it iss known that 40% of radio listeneres at a particuar college are smokers. A sample of 400 students from the college is selected at random. Approximate the probability that at least 180 of these students are radio listeners.
Solution
We are given that 40% of radio listeneres at a particuar college are smokers.
that is it is known that p = 40% = 40/100 = 0.4
number of students from college (n) = 400
We have to calculate probability that at least 180 of these students are radio listeners.
sample proportion (p^) = number of students are radio listeners / n
p^ = 180 / 400 = 0.45
We have to find P(p^ > 0.45)
We can find this probability by using normal distribution.
We know that sample proportion (p^) follows normal distribution with mean p and standard deviation (SD) is
sqrt( (p*q)/n ).
where q = 1 - p
q = 1 - 0.4 = 0.6
SD = sqrt ((p*q)/n ) = sqrt ((0.4*0.6)/400) = 0.0245
P( (p^-p) / sqrt((p*q)/n) > (0.45 - p) / sqrt((p*q)/n) ) = P(Z > (0.45 - 0.4) / sqrt((0.4*0.6) /400)
P(Z > 2.0412) = 1 - P(Z <=2.0412)
This probability we can find by using EXCEL.
Statistical table and EXCEL always gives left tail probability.
syntax :
=NORMSDIST(z)
where, z is test statistic value = 2.0412
P(Z <=2.0412) = 0.9794
P(Z > 2.0412) = 1 - 0.9794 = 0.0206

