105 pointssercp10 6p054nva Consider a frictionless track as

10.-/5 pointssercp10 6.p.054.nva Consider a frictionless track as shown in the figure below. A block of mass m1 = 5.10 kg is released from . It makes a head-on elastic collision at C with a block of mass ma = 19.5 kg that is initially at rest. Calculate the maximum height to which m1 rises after the collision (No Response) m 5.00 m M-

Solution

m1 =5.1 kg , m2 =19.5 kg h1 = 5 m

From conservation of energy at A and B points

P.E =K.E

mgh = (1/2)mu1^2

u1^2 = 2*9.8*5 = 9.9 m/s

u2 =0

From conservaiton of momentum

m1u1+m2u2 =m1v1+m2v2

(5.1*9.9) +0 = (5.1*v1)+(19.5*v2) ... (1)

for elasti collision

v2 -v1 = u1 -u2

v2 -v1 = 9.9 ... (2)

by solving (1) and (2) we get

v1 = -2.9 m/s

v2 = 7.11 m/s

from conservation of energy

mgH = (1/2)mv1^2

H = (2.9*2.9)/(2*9.8)

H = 0.43 m