I would really appreciate a fully detailed complete answer

Solution

(a). V1=V2= 5 v

D1 and D2 are in forward bais, because

vd= voltage across diode= 5-V1= 0, hence it is forward bais

Apply kcl at node vout.

(Vout-5)/10=(vout-v1)/1+(vout-v2)/1

(Vout-5)/10= 2vout-10

Vout-5=20Vout-100

Vout=95/19=5 v

(b) both diode is in forward bais.

Apply kcl at node Vout.

(Vout-5)/10=(vout-v1)/1+(vout-v2)/1

(Vout-5)/10= 2vout-5

Vout-5=20Vout-50

Vout=45/19=2.36v

(C) both diode is in forward bais.

Apply kcl at node Vout.

(Vout-5)/10=(vout-v1)/1+(vout-v2)/1

(Vout-5)/10= 2vout-

Vout-5=20Vout

Vout=5/19=0.26 v