Homework Sourseb A new experiment is created with the screen at a distance
(b) A new experiment is created with the screen at a distance of 2.2 m from the slits (with spacing 0.1 mm). What is the distance between the second order bright fringe of light with l= 697 nm and the third order bright fringe of light with l = 413 nm? (Give the absolute value of the smallest possible distance between these two fringes: the distance between bright fringes on the same side of the central bright fringe.)
(b) A new experiment is created with the screen at a distance of 2.2 m from the slits (with spacing 0.1 mm). What is the distance between the second order bright fringe of light with l= 697 nm and the third order bright fringe of light with l = 413 nm? (Give the absolute value of the smallest possible distance between these two fringes: the distance between bright fringes on the same side of the central bright fringe.)
Solution
D = 2.2 m, a = 0.1 * 10-3 m
|x| = x1 - x2 = D/a * (2 * 697 * 10-9 - 3 * 413 * 10-9 )
= 2.2 / (0.1 * 10-3) * (2 * 697 * 10-9 - 3 * 413 * 10-9 )
= 3.41 mm
