Homework SourseWater flows from the bottom of a storage tank at a rate of r
Water flows from the bottom of a storage tank at a rate of r(t)=200-4t liters per minute, where 0<=t<=50. Find the amount of water that flows from the tank during the first ten minutes
Solution
integrate r(t) with respect to t from 0 to 10 Integrate r(t) dt = 200t -(4t^2)/2 + C = 200t -2t^2 + C where C is a constant hence the amount of water flows during first 10 mins is = {200*10 - 2*(10)^2 + C} - {200*0 - 2*(0)^2 + C} = {2000 - 200} - {0 - 0} = 1800 liters
