A rotating circular restaurant at the top of a hotel has a d

A rotating circular restaurant at the top of a hotel has a diameter of 32.5 m. If it completes one revolution in 24.0 min, what is the velocity of the outer surface?

Solution

Here the radius = 32.5 = 16.25 m

so angular velocityy of the outer surface = 2pi x 24 = 48 pi

and thus its linear velocity = 48 pi x 16.25 = 48 x 3.14 x 16.25

= 2449.2 m per min.

Answer