y2xx2 find the y and x intercept x12y3236 find the center an

y=2x-x^2

find the y and x intercept.

(x+1)^2+(y-3)^2=36

find the center and radius

y = 2x - x^2

to find x intercept plug y=0

0 = 2x - x^2

taking out the gcf x

0 = x ( 2 - x)

applying zero product property

x = 0

2-x = 0

x = 2

the 2 x intercepts are

x = 0 , x = 2

to find y intercept plug x =0

y = 2(0) - 0^2

y = 0

there is only one y intercept y = 0

2) ( x+ 1)^2 + (y-3)^2 = 36

standard equation of circle is

( x-h)^2 + (y-k)^2 = r^2

where , h , k is the centre and r is the radius

comparing the two equations we get

h = -1

k = 3

r^2 = 36

r = 6

hence , centre is ( -1 , 3)

radius is 6