A car of weight 1680 N operating at a rate of 149 kW develop

A car of weight 1680 N operating at a rate of 149 kW develops a maximum speed of 29 m/s on a level, horizontal road. Assuming that the resistive force (due to friction and air resistance) remains constant, what is the car\'s maximum speed on an incline of 1 in 20; i.e., if theta is the angle of the incline with the horizontal, sin Tata = 1/20 ? Answer in units of m/s. As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force? The power stays the same. The power decreases. The power increases. Unable to determine

Solution

Power = force * velocity

force = power / velocity = 149000 / 29 = 5138 N

v\' = P / f + W sin theta

= 149 * 10³ / [5138 + 1680/20]

= 28.53 m/s

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The power increases