Homework Sourseapproximately 20 of 1000 fish in a pond are infected with a
approximately 20% of 1000 fish in a pond are infected with a skin disease. A random sample of 20 fish is selected. The mean of the sample lien distribution for the proportion of your sample that is infected is
approximately 20% of 1000 fish in a pond are infected with a skin disease. A random sample of 20 fish is selected. The mean of the sample lien distribution for the proportion of your sample that is infected is
approximately 20% of 1000 fish in a pond are infected with a skin disease. A random sample of 20 fish is selected. The mean of the sample lien distribution for the proportion of your sample that is infected is
Solution
proportion of fish infected = 20% = 0.20
Population size N = 1000
Sample size = n = 20
The mean of the sample would be np
= 20(20/100)
= 4
