A batch of 300 parts contains 3 defective units What is the

A batch of 300 parts contains 3 defective units. What is the probability of a sample of three parts pulled for analysis will be:

A: None defective?

B: All Defective?

C.At least defective?

D: At least non defective?

Solution

There are 300C3 = 4455100 ways to choose 3 units.

A)

There are 297C3 = 4322340 ways to choose 3 non-defective.

Hence,

P(all non def) = 4322340/4455100 = 0.970200444 [answer]
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B)

There is only one way to choose all three defective. Hence,

P(all def) = 1/4455100 = 0.000000224462 [answer]

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Please check parts C and D, I think there should be a number there.

Please resubmit them as separate questions, and write the sentence that describes the problem. Thanks!