A company has a quote for possible job that is normally dist

A company has a quote for possible job that is normally distributed with a mean = 3.6 days and standard deviation = 1.2 days. What is the probability that of a response for this bid is within 2 days ?

Solution

mean = 3.6

sd = 1.2

x = 2

z = (x-mean)/sd

z = (2-3.6)/1.2

z= -1.33

P(z<-1.33) = 0.0918

A company has a quote for possible job that is normally distributed with a mean = 3.6 days and standard deviation = 1.2 days. What is the probability that of a

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