what is the polar coordinates r0 for 636Solution 63 6 21

what is the polar coordinates (r,0) for (-6^3,6)

Solution

( -6^3 , 6 )

= ( -216 , 6)

r = sqrt (x^2 + y^2 )

r = sqrt ( 216^2 + 6^2)

r = 216.08

theta = tan^-1 ( y/x)

theta = tan^-1 ( -216 / 6 ) = 178.408

hence, polar coordinates are

(r , theta ) = ( 216.08 , 178.408 )