Find the rectangular coordinates for 1 pi3Solutiongiven r 1

Find the rectangular coordinates for (-1, - pi/3)

Solution

given r =-1,=-/3

x=rcos , y=rsin

x=-1cos(-/3) , y =-1sin(-/3)

x =-1(cos(/3)), y =-1(-sin(/3))

x =-cos(/3), y =sin(/3)

x =-1/2, y=(3)/2

rectangular coordinates are (-1/2,(3)/2)

 Find the rectangular coordinates for (-1, - pi/3)Solutiongiven r =-1,=-/3 x=rcos , y=rsin x=-1cos(-/3) , y =-1sin(-/3) x =-1(cos(/3)), y =-1(-sin(/3)) x =-cos(

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