I need help constructing the most parsimonious tree Ive alre

I need help constructing the most parsimonious tree. I\'ve already created a chart with the characteristics but don\'t know where to go from there

Part I: Below is a list of imaginary species (A-G) and some of their traits: Species Character traits A blue spots, no scales, green eyes, no wings, no claws, no horns, live birth, tail, carnivore, hair B no spots, scales, red eyes, no wings, claws, no horns, egg layer, ta carnivore, no hair C no spots, scales, red eyes, no wings, claws, no horns, egg layer, tail, herbivore, no hair D blue spots, no scales, green eyes, no wings, no claws, horns, live birth, tail, carnivore, hair E green spots, no scales, red eyes, wings, claws, no horns live birth, no tail, carnivore, no hair F blue spots, no scales, green eyes, no wings, claws, no horns, live birth, tail, camivore, no hair G green spots, no scales, red eyes, no wings, claws, horns, live birth, no tail, carnivore, no hair Assume that the ancestor of this group, the extinct lineage at the root of the tree, had the following features: Bo spots, seales, red eyes, no wings, claws, no horns, egg layer, tail, herbivore, no hair. Using these characters and cladistic methods, construct the most parsimonious phylogeny for the group and draw this tree below. Remember that the most parsimonious tree is the one with the fewest possible evolutionary changes (see Ch 2 ofFutuyma), Then indicate where each change occurred (i.e., where derived character states first appeared) on branches of the tree. Thus, if there was a change from \"claws\" to \"no claws\' on a branch, you would indicate either \"no claws\' or \'elaws lost\" (18 points)

Solution

First look all the characteristics of the given species. We can see that

1. All the characteristics of \"C\" matches with the ancestral characteristics. So \"C\" can be the ancestor.

2. Out of 10 ancestral characters, 9 characters in \"B\" species matches with the ancestor.

3. \"F\" species have 5 common characteristics.

4. Species E, G has 4 characteristics in common.

5. \"A\" has 3 characters in common and \"D\" has only 2 common characters when compared with the ancestral characteristics.

So, species A and D will have very far relationship with the ancestor \"C\"

--------------> E -------------> A -------------> D

C -----------> B ------------> F ---------- (or)

--------------> G -------------> A -------------> D