The links of individual fish in a pond have an approximate n
The links of individual fish in a pond have an approximate normal distribution with a mean of 18.6 cm and a standard deviation of 6.0 cm. a sample of 36 fish is taken. what is the standard deviation of the sample lien distribution of the sample mean for the 36 fish?
 The links of individual fish in a pond have an approximate normal distribution with a mean of 18.6 cm and a standard deviation of 6.0 cm. a sample of 36 fish is taken. what is the standard deviation of the sample lien distribution of the sample mean for the 36 fish?
 The links of individual fish in a pond have an approximate normal distribution with a mean of 18.6 cm and a standard deviation of 6.0 cm. a sample of 36 fish is taken. what is the standard deviation of the sample lien distribution of the sample mean for the 36 fish?
Solution
The standard deviation of the sample link distribution is also known as the standard error of the sampling distribution. The standard error of the sampling distribution is defined as -
SE = population standard deviation / sqrt (n)
where n is the sample size.
so, in this case SE = 6/ sqrt(36)
=> SE = 6 / 6 = 1
So, the standard deviation of the sampling distribution of the sample mean for 36 fishes = 1.

