For the configuration shown take the scale to be attached to

For the configuration shown, take the scale to be attached to the plate, which is free to turn about the central support Take the plank is be very light (i.e, massless) If the system is in rotational equilibrium, find: The reading of the scale (in kilogarms) The reaction force at the central support.

Solution

1. Resolving vertically, aplied force of 150N at 30deg = 75 N upward

Moments about central support give: 75*3 - 5*2*g + 2*S =0 ( assuming 5kg is mass not weight force)units (N.m)

S = scale force = -63.45 N (upward force). = 6.467 kg mass

b) central reaction vertical [( 20+5)-6.567]g-75 N = 105,8 N

Horiz reaction 150cos30 N = 129.9N

 For the configuration shown, take the scale to be attached to the plate, which is free to turn about the central support Take the plank is be very light (i.e,

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