Sin3 beta cos3 betasin beta cos beta 1 sin beta cos beta

Sin^3 beta + cos^3 beta/sin beta + cos beta = 1- sin beta cos beta

b)(sin³B+cos³B)/(sinB+cosB)

a³+b³=(a+b)(a²+b²-ab)

=(sinB+cosB)(sin²B+cos²B-sinBcosB)/(sinB+cosB)

=(sin²B+cos²B-sinBcosB)

sin²x +cos²x =1 is an identity

=(1-sinBcosB)

Sin^3 beta + cos^3 beta/sin beta + cos beta = 1- sin beta cos beta Solutionb)(sin3B+cos3B)/(sinB+cosB) a3+b3=(a+b)(a2+b2-ab) =(sinB+cosB)(sin2B+cos2B-sinBcosB)

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