Given the function fx 3x 2 Find an equation of the secant l

Given the function f(x) = 3x +2. Find an equation of the secant line passing through the points x = -1 and x = 0.

(write your answer in the form y = mx + b ).

for x=-1 ; f(-1) = 3(-1) +2 = -1

for x=0 ; f(0) = 2

We have two points: ( -1. -1) and ( 0,2)

Slope of line passing throwugh these two points : m = (2 +1)/(0+1) = 3

y = mx+c ---> y = 3x+c

-1 = -3 +c

c=2

So, eqution of secant : y = 3x +2