A building contractor buys 90 of his cement from supplier A
     A building contractor buys 90% of his cement from supplier A and 10% from supplier B. A total of 70% of the bags from A arrive undamaged, and a total of 75% of the bags from B arrive undamaged. Find the probability that a damaged bag is from supplier B. The probability is  (Round your answer to three decimal places, is necessary.)  
  
  Solution
total number of damaged bags = 90% * 0.3 + 10% * 0.1 = 28%
number of damaged bags from A = 90% * 0.3 = 27%
probability = 27/28 = 0.964

