Homework SourseP541 An AISI 1040 hotrolled steel E 207 GPa 113106C bar is
P5.41 An AISI 1040 hot-rolled steel [E = 207 GPa; = 11.3×10-6/°C] bar is held between two rigid supports. The bar is stress free at a temperature of 25°C. The bar is then heated uniformly. If the yield strength of the steel is 414 MPa, determine the temperature at which yield first occurs ![P5.41 An AISI 1040 hot-rolled steel [E = 207 GPa; = 11.3×10-6/°C] bar is held between two rigid supports. The bar is stress free at a temperature of 25°C. The](/WebImages/29/p541-an-aisi-1040-hotrolled-steel-e-207-gpa-113106c-bar-is-1081238-1761567826-0.webp "P5.41 An AISI 1040 hot-rolled steel [E = 207 GPa; = 11.3×10-6/°C] bar is held between two rigid supports. The bar is stress free at a temperature of 25°C. The")
Solution
Stress = 414 MPa
E= 207000 MPa
Strain = stress/E
= 414/207000
=0.002
strain = (alpha)*(T2-T1)
0.002= 11.3*10-6(T2-25)
T2=201o C
