zxandzy as functions of x y and z assuming that the function
?z?xand?z?y as functions of x, y, and z, assuming that the function z=f(x,y) is given implicitly by the equation x^3 + xyz = yz.
Solution
differentiate with respect to x:
d/dx (x^3 + xyz = yz)
3x^2 + y*z + (xy)(dz/dx) = y(dz/dx)
(dz/dx)(y-xy) = 3x^2 + yz
thus z/x = (3x^2 + yz)/(y-xy)
now differentiate with respect to y:
d/dy (x^3 + xyz = yz)
0 + x*z + (xy)(dz/dy) = y(dz/dx) + 1*z
(dz/dx)(y-xy) = xz-z
thus z/y = (xz-z)/(y-xy) = z(x-1)/y(1-x) = -z/y
