Shuttle bus comes to a sudden stop to avoid hitting a dog it

Shuttle bus comes to a sudden stop to avoid hitting a dog, it accelerates uniformly at -4.8m/s to the second power as it slows from 8.3m/s to 0m/s.

find the time the interval of acceleration for the bus. answer in units of s.

The final velocity,v of the bus after hit = 0 (halts)

The initial velocity u of the bus before hitting(or before applying break) = 8.3m/s

The acceleration of the a = -4.8ms^-2 , -ve .

Therefore, a = (v-u)/t, where t is the time in secs. Substituting the values,

-4.8 = (0-8.3)/t= -8.3/-4.8=1.93 secs

Therefore, the bus took 1.93 secs to come to rest