For the standard normal distribution find the area between t

For the standard normal distribution, find the area between the z scores of -1.50 and 2.50.

Solution

Normal Distribution
Mean ( u ) =0
Standard Deviation ( sd )=1
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
To find P(a < = Z < = b) = F(b) - F(a)
P(X < -1.5) = (-1.5-0)/1
= -1.5/1 = -1.5
= P ( Z <-1.5) From Standard Normal Table
= 0.06681
P(X < 2.5) = (2.5-0)/1
= 2.5/1 = 2.5
= P ( Z <2.5) From Standard Normal Table
= 0.99379
P(-1.5 < X < 2.5) = 0.99379-0.06681 = 0.927