Consider the following class definitions virtually identical

Consider the following class definitions (virtually identical to those used in class): class IntNode {int datum;//datum to be stored IntNode next;//next item in list public int getDatum() {return datun;} public void setDatum(int which) {datum = which;} public IntNode getNext() {return next;} public IntNode setNext(IntNode which) {next = which;}} class LinkedList {IntNode head;//first item in the list; public LinkedList() {head = null;}} Each of the following methods is a member of the LinkedList class. All the methods compile correctly: however, they do not function as described in their headers. What is wrong? How would you fix them?//This method counts the number of items in the list. public int length () {int count = 1; IntNode current = head; while (current.getNext() ! = null) {current = current.getNext(); count++;} return count;}//This method places \"target\" at the front of the list public void prepend (int target) {IntNode newNode = new IntNode(); newNode.setDatum(target); head = newNode; newNode.setNext(head);}//This method searches a sorted list for \"target\"//Assumption: all numbers in the list are sorted//from small to large public boolean search (int target) {if (head == null) return false; IntNode current = head; while (current.getDatum()

Solution

5) Answer

import java.util.Scanner;
class palindrome
{
//Recursive method to check palindrome
public static boolean isPalin(String str)
{   
   // If length is 0 or 1 then String is palindrome
if(str.length() == 0 || str.length() == 1)
return true;
if(str.charAt(0) == str.charAt(str.length()-1))

// Check for first and last char of String. If they are same then do the same thing for a substring with first and last char removed.
   // Continue this until our string completes or condition fails.
return isPalin(str.substring(1, str.length()-1));

return false;
}

public static void main(String[]args)
{
   //Scanner class object is created
Scanner scanner = new Scanner(System.in);
System.out.println(\"Enter the String for check:\");
   //Accept a string
String string = scanner.nextLine();

// If function returns true then the string is palindrome else not palindrome
if(isPalin(string))
System.out.println(string + \" Palindrome\");
else
System.out.println(string + \" Not Palindrome\");
}
}

Output 1:

Enter the String for check:
thisis
thisis Not Palindrome

Output 2:

Enter the String for check:
madam
madam Palindrome

4) Answer:

public int average()
{
   int sum = 0;
   int cou = 0;
   IntNode current = head;
   //Checks for empty
   if (head == null)
       return 0;
   //Loops till end of the linked list
   while(current.getNext() != null)
   {
       //Calculates total  
       sum = sum + current.getDatum();
       //Counter for number of items
       cou++;
   }
   System.out.println(\"Average of the elements in the list = \" + (sum / cou));
}