PX

P(X<2), n=5, p=0.7

P(X<2), n=5, p=0.7

X is a binomial with n =5 and p =0.7

Hence P(X<2) = P(X=0)+P(X=1)

= 5C0(0.3)⁵+ 5C1(0.7)(0.3)⁴

= 0.00243+0.02835 = 0.03078

P(X<2), n=5, p=0.7 P(X<2), n=5, p=0.7SolutionX is a binomial with n =5 and p =0.7 Hence P(X<2) = P(X=0)+P(X=1) = 5C0(0.3)5+ 5C1(0.7)(0.3)4 = 0.00243+0

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