A binary encoded signal has a bitrate of Rb 28 kbps An Alte
A binary encoded signal has a bit-rate of Rb = 28 kbps. An Alternate Mark Inversion line-code is used to encode these bits for baseband transmission over copper wire. What would be the transmission bandwidth required to transmit this signal? B = 112 kHz B = infinity B = 28 kHz B = 56 kHz B = 14 kHz B = 7 kHz
Solution
Speed or bit rate = nfs = Rb
Bandwidth minimum is Rb/2
Bandwidth maximum is Rb
Normally bandwidth consider to be half of speed
Bandwidth = 28/2
Bandwidth = 14 kbps
