Let X be an exponential random variable with parameter and m
Let X be an exponential random variable with parameter and moment generating function mX(t) = /( – t). Let random variable Y = 2X. Then the moment generating function of Y is
mY(t) = /( – 2t)
mY(t) = /(2 – t)
mY(t) = /( – t)2
mY(t) = 2/( – t)
| Let X be an exponential random variable with parameter  and  moment generating function mX(t) = /( – t). Let random  variable Y = 2X. Then the moment generating function of Y is A. mY(t) = /( – 2t) | |
| B. None of the given mgf’s. | |
| C. mY(t) = /(2 – t) | |
| D. mY(t) = /( – t)2 | |
| E. mY(t) = 2/( – t) | 
Solution
If X and Y have same distirbution then mX(t)=mY(t) in that situation the answer is (A).
Otherwise if answer (E) is correct

