In a population of red recessive and blank beetles in HW equ

In a population of red (recessive) and blank beetles in HW equilibrium, the frequency of black beetles is 91%.What id the frequency of the black allele? If the frequency of red beetles is 91%, what are the phenotype frequencies? The genotype frequencies? The allele frequencies? How many of each genotype in a population of 10000 beetles? Assume HW equilibrium.

Solution

Answer:

A).

Black (dominant) phenotypes= 91%

Red (recessive) phenotypes= 9%

Red phenotype frequency = q2= 9/100=0.09

Red allele frequency = q= 0.3

p+q= 1

p=1-q= 1-0.3=0.7

The black allele frequency= p= 0.7

B)

Red phenotype, rr frequency = q²= 91/100=0.91

Red allele, r frequency = q = 0.95

p+q= 1

p=1-q= 1-0.95=0.05

The black allele, R frequency= p= 0.05

Red phenotype, rr frequency = q² =   0.91

Black (homozygous) phenotype, RR frequency = p² = 0.05 * 0.05 = 0.0025

Black (heteroozygous) phenotype, Rr frequency = 2pq = 2 * 0.05 * 0.95 = 0.095

Black, RR beetles = 0.0025 * 10000= 25

Black, Rr beetle= 0.095 * 10000= 950

Black, rr beetle= 0.91 * 10000= 9100