R1 SolutionAns Given VS25 VR122kR268 k As in series circuits

Ans) Given VS=25 V,R1=22k,R2=68 k

As in series circuits current is same I1=I2=Vs/(R1+R2)

I1=I2=25/(22+68)k=0.278 mA

1.Ans Power Delivered by Voltage source =Vs*I1=25*0.278m=6.94 mW

So Ps=6.94 mW

2.Ans Power dissipated R1 ----P1=I1^2*R1=(0.278m)^2*22k=1.7 mW

-R2------P2=I2^2*R2=(0.278m)^2*68k=5.24 mW

3.Ans Ps=P1+P2=1.7+5.24=6.94 mW=Ps