Yo just need verificationclarification aaBbCcDdee x AaBbCcdd

Yo, just need verification/clarification:

aaBbCcDdee x AaBbCcddEE

probability of any individual offspring with genotype AaBbCcDdEe or aabbCCddEe?

I arrived at 5/64, yes, no?

do not pass go? mind moving too slow?

I added up the separate probabilities for AaBbCcDdEe,

which I got by multiplying the probability for each individual Punnett squares for A, B, C, D, E cross,

is that correct?

Just a little uncertainty on when to add versus multiply ratios,

thanks for lightening the load before I explode,

Max

Solution

Answer:

The probability of obtaining AaBbCcDdEe is: Aa=½; Bb= ½; Cc=½; Dd=½; Ee=1 = ½ x ½ x ½ x ½ x 1 =1/16

The probability of obtaining aabbCCddEe is: aa=½; bb= ½ ; CC=¼; dd=½; Ee=1 = ½ x ½ x ¼ x ½ x 1 =1/32

the chances of getting either a AaBbCcDdEe or a aabbCCddEe are: (probability of getting AaBbCcDdEe) + (probability of aabbCCddEe) = 1/16 + 1/32 = 38/512= 19/256