In the following exercise find the coordinates of the vertex

In the following exercise, find the coordinates of the vertex for the parabola defined by the given quadratic function. f(x) = - 4(x + 4)^2 + 1 The vertex is square (Type an ordered pair.)

Solution

Here, f(x) = -4(x+4)² + 1. The vertex form of the equation of a parabola is y = f(x) = a (x – h)² + k , where (h, k) is the vertex. Here, a = - 4, h = - 4 and k = 1. Thus, the vertex of the given parabola is the point ( - 4,1)