For which R is 2 22 12 32 0SolutionSolution 2 22 12 32 0 0

For which R is (^2 2)(^2 +1)(^2 3+2) = 0?

Solution

Solution:

(^2 2)(^2 +1)(^2 3+2) = 0

=0 or

(^2 2)=0

^2 =2

=± 2 or

^2 +1=0

^2=-1

^2=i² (since i² =-1)

=±i or

^2 3+2=0

factorize to get the lambda value.If we multiply result should be +2 and if we add the result should be -3

-2*-1=+2

-2-1=-3.

we write -3 as -2-1

^2 2 -+2=0

(-2)-1(-2)=0

(-2)((-1)=0

-2=0 or -1 =0

=2 or =1

for =2 or =1 is R  is zero.