Please show workSolution1 x34x x2 3x 18x2 16 factorise x2 3

Please show work!

1) (x-3)/(4-x) /(x^2 +3x -18)/(x^2 -16)

factorise : (x^2 +3x -18)/(x^2 -16)

= (x^2 +6x -3x -18)/(x+4)(x-4)

= (x+6)(x-3)/(x+4)(x-4)

(x-3)/(4-x) /(x^2 +3x -18)/(x^2 -16) = -(x-3)/(x-4) /(x^2 +3x -18)/(x^2 -16)

=-(x-3)/(x-4) / (x+6)(x-3)/(x+4)(x-4)

= - (x-3)*(x+4)(x-4)/(x-4)(x+6)(x-3)

= -(x+4)/(x+6)

2) 13/(x-5) -x = -5x+12/(5-x)

= ( 5x-12)/(x-5)

Taking (x-5) as lcd on both sides:

(13 -x(x-5) )/(x-5) = (5x-12)/(x-5)

cancel denominator:

(13 -x^2 +5x ) = 5x -12

-x^2 +5x +13 = 5x -12

-x^2 = -25

x^2 = 25

x= +/- 5 (solution)