What volume of 020 M H2SO4 is required to produce 340g H2S b

What volume of 0.20 M H2SO4 is required to produce 34.0g H2S by the following reaction with excess Kl?

8Kl + 5H2SO4 -> 4K2SO4 + 4I2 + H2S + 4H2O

Solution

34 gram of H2S= 1 mole from the equation, we observe that for 1 mole of H2S, 5 mole of H2SO4 is required

volume of H2SO4 required= moles required/ (conentration of solution per litre)

V=5/0.2=25 litre