For each of the following compute the future value Do not ro
Solution
We use the formula:
A=P(1+r/100)^n
where
A=future value
P=present value
r=rate of interest
n=time period
a.
1.
A=$2050*(1.12)^12
=$2050*3.895975993
=$7986.75(Approx).
2.
A=8352*(1.1)^6
=$8352*1.771561
=$14796.08(Approx).
3.
A=72355(1.11)^13
=$72355*3.883280163
=$280974.74(Approx).
4.
A=179796*(1.07)^7
=$179796*1.605781476
=$288713.09(Approx).
b.
1.
1488=550(1.1)^n
(1488/550)=(1.1)^n
Taking log on both sides;
log(1488/550)=n*log 1.1
n=log(1488/550)/log 1.1
=10.44 years(Approx).
2.
1922=800(1.11)^n
(1922/800)=(1.11)^n
Taking log on both sides;
log(1922/800)=n*log 1.11
n=log(1922/800)/log 1.11
=8.40 years(Approx).
3.
244179=18300(1.16)^n
(244179/18300)=(1.16)^n
Taking log on both sides;
log(244179/18300)=n*log 1.16
n=log(244179/18300)/log 1.16
=17.46 years(Approx).
4.
290433=21400(1.13)^n
(290433/21400)=(1.13)^n
Taking log on both sides;
log(290433/21400)=n*log 1.13
n=log(290433/21400)/log 1.13
=21.34 years(Approx).

