C Write a function that finds the smallest the largest elem

C++

Write a function that finds the smallest & the largest element of a
vector
        argument and also compute the mean and the median. Do not use global
variables.
        Either return a struct containing results or pass them back through
reference
        arguments. Which of the 2 ways of returning several result values do
you prefer and why?

Solution

The program which is related to the asked question is and please let me know if any error occurs:

struct stats {

vector<double> v;

double mean;

double median;

double max;

double min;

};

void fmean(stats& results)

{

results.mean = sum/results.v.size();

}

void fmedian(stats& results)

{

sort(results.v.begin(), results.v.end());

if (results.v.size()%2 == 0)

results.median = (results.v[results.v.size()/2] + results.v[results.v.size()/2-1])/2;

else

results.median = results.v[results.v.size()/2];

}

void fmin_max(stats& results)

{

results.max = results.min = results.v[0];

for (unsigned int i = 0; i < results.v.size(); ++i) {

if (results.v[i] > results.max)

results.max = results.v[i];

if (results.v[i] < results.min)

results.min = results.v[i];

}                             

}

int main()

try {

stats myresults;

cout << \"Enter some elements: \ \";

double x;

while (cin >> x)

myresults.v.push_back(x);

fmedian(myresults);

fmean(myresults);

fmin_max(myresults);

cout << \"Mean: \" << myresults.mean << \'\ \';

cout << \"Median: \" << myresults.median << \'\ \';

cout << \"Max: \" << myresults.max << \'\ \';

cout << \"Min: \" << myresults.min << \'\ \';

}

catch (runtime_error e) {

cout << e.what();

}