Discrete Random Variables we are working with commonly used
Discrete Random Variables
we are working with commonly used discrete and continuous distribution
Solution
3.
Here,
P(complete) = 1 - 0.2 = 0.8.
Note that P(at least x) = 1 - P(at most x - 1).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 10
p = the probability of a success = 0.8
x = our critical value of successes = 9
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 8 ) = 0.624190362
Thus, the probability of at least 9 successes is
P(at least 9 ) = 0.375809638
Thus, if this happens to both groups,
P(both groups have at least 9 completers) = 0.375809638*0.375809638 = 0.141232884 [ANSWER]
