2 Given x Px 4 040 7 025 10 035 a List ALL the conditio
2. Given
x | P(x)
– 4 | 0.40
7 | 0.25
–10 | 0.35
a. List ALL the conditions that shown above is a probability distribution.
b. Find the mean of the probability distribution.
c. Find the standard deviation.
Solution
a) P(X) >0
ii) Total prob = 0.40+0.25+0.35 = 1
Hence all conditions are satisfied hence a prob distribution
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b) To find mean and std dev
Hence Mean of x = -3.35
E(X^2) = 53.65
Var(X) = 53.65-3.352
=42.4275
Std dev(X) = 6.514
| x | p(x) | xp | x^2p |
| -4 | 0.4 | -1.6 | 6.4 |
| 7 | 0.25 | 1.75 | 12.25 |
| -10 | 0.35 | -3.5 | 35 |
| Sum | 1 | -3.35 | 53.65 |
